Answer:
[tex]A_2=0.74\ m^2[/tex]
Explanation:
Given that,
Weight, F₁ = 15,000 N
Area, A₁ = 10 m²
Weight, F₂ = 1100 N
We need to find the area of the small piston. The pressure exerted on both piston will be equal such that,
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\A_2=\dfrac{F_2A_1}{F_1}\\\\A_2=\dfrac{1100\times 10}{15000}\\\\A_2=0.74\ m^2[/tex]
So, the area of the smaller piston is [tex]0.74\ m^2[/tex].
