Answer: -6<x<5
Step-by-step explanation:
Given
Length is 3 m more than three times the width
Suppose width is x
So, the length is 3x+3
The area of a rectangle is [tex]length\times width[/tex]
Area= [tex](3x+3)x<90[/tex]
[tex]\Rightarrow 3x^2+3x-90<0\\\Rightarrow x^2+x-30<0\\\Rightarrow x^2+6x-5x-30<0\\\Rightarrow (x+6)(x-5)<0\\\Rightarrow -6<x<5[/tex]