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Write an equation in point-slope form of the line having the given slope that contains the given point. then graph the line

(dont think u can graph so its okay)

Write an equation in pointslope form of the line having the given slope that contains the given point then graph the line dont think u can graph so its okay class=

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absor201

Answer:

The line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

[tex]y +1 = \frac{1}{2} (x-3)[/tex]

Please check the attached graph.

Step-by-step explanation:

Given

  • The slope m = 1/2
  • The point (3, -1)

Point slope form:

[tex]y-y_1=m\left(x-x_1\right)[/tex]

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

m = 1/2

The point (x₁, y₁) = (3, -1)

substituting the values m = 1/2 and the point  (x₁, y₁) = (3, -1)  in the point-slope form of the line equation

[tex]y-y_1=m\left(x-x_1\right)[/tex]

[tex]y - (-1) = \frac{1}{2} (x-3)[/tex]

[tex]y +1 = \frac{1}{2} (x-3)[/tex]

Thus, the line of the equation in the point-slope form of the line passing through the point (3, -1) and having slope 1/2 will be:

[tex]y +1 = \frac{1}{2} (x-3)[/tex]

Please check the attached graph.

Ver imagen absor201

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