Respuesta :
Answer:
The magnitude of the gravitational force of attraction between the two objects when they are 416 meters apart is;
D. 4.5 × 10⁻¹⁰ Newtons
Explanation:
The given parameters are;
The distance between the center of mass of the cow and the tractor, r = 208 m
The gravitational attraction between the cow and the tractor = 1.8 × 10⁻⁹ N
The formula for finding the gravitational force, 'F', between the cow and the tractor is given as follows;
[tex]F =G\cdot \dfrac{m_{1} \cdot m_{2}}{r^{2}}[/tex]
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹m³·kg⁻¹·s⁻²
m₁·m₂ = The product of the mass of the cow and the tractor
Therefore, we have;
[tex]F = 1.8 \times 10^{-9} =G\cdot \dfrac{m_{1} \cdot m_{2}}{208^{2}}[/tex]
1.8 × 10⁻⁹ × 208² ≈ 7.78752 × 10⁻⁵ = G × m₁ × m₂
Therefore, when the distance between the two objects are 416 meters apart, we have;
[tex]F = \dfrac{G \cdot m_{1} \cdot m_{2}}{r^{2}} = \dfrac{7.78752 \times 10^{-5}}{416^2} = 4.5 \times 10^{-10}[/tex]
The magnitude of the gravitational force of attraction between the cow and the tractor when they are 416 meters apart, F = 4.5 × 10⁻¹⁰ N.
