The new temperature(T₂) : T₂=596 K = 323 °C
Further explanation
Given
T₁ = 25 C + 273 = 298 K
V₁ = 10 m³
V₂ = 20 m³(doubled)
Required
The new temperature(T₂)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
Input the value :
T₂=(V₂.T₁)/V₁
T₂=(20.298)/10
T₂=596 K = 323 °C
