Complete Question:
When a 40.0-g nugget of pure gold is heated from 49°C to 60.0°C, it absorbed 5339.01 of energy. What is
the specific heat of gold?
Answer:
Specific heat capacity, c = 12.134J/KgC
Explanation:
Given the following data;
Mass = 40g
Initial temperature, T1 = 49°C
Final temperature, T2 = 60.0°C
Quantity of heat = 5339.01J
To find the specific heat capacity of gold;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
dt = T2 - T1
dt = 60 - 49
dt = 11°C
Substituting the values into the equation, we have;
[tex] 5339.01 = 40*c*11 [/tex]
[tex] 5339.01 = 440c [/tex]
[tex] c = \frac {5339.01}{440} [/tex]
Specific heat capacity, c = 12.134J/KgC
