Answer:
The ramp must cover a horizontal distance of approximately 19.081 feet.
Step-by-step explanation:
Given the vertical distance ([tex]y[/tex]), measured in feet, and the angle of the wheelchair ramp ([tex]\theta[/tex]), measured in sexagesimal degrees. The horizontal distance needed for the ramp ([tex]x[/tex]), measured in feet, is estimated by the following trigonometrical expression:
[tex]x = \frac{y}{\tan \theta}[/tex] (1)
If we know that [tex]y = 1\,ft[/tex] and [tex]\theta = 3^{\circ}[/tex], then the horizontal distance covered by this ramp is:
[tex]x = \frac{1\,ft}{\tan 3^{\circ}}[/tex]
[tex]x \approx 19.081\,ft[/tex]
The ramp must cover a horizontal distance of approximately 19.081 feet.
