Answer:
(x + 3) - x(x² + 6x + 9)
= (x + 3) - x(x + 3)²
= (x + 3)[1 - x(x + 3)]
= (x + 3)(1 - x² - 3x)
Step-by-step explanation:
Answer:
[tex](x+3)(1-x^2-3x)[/tex]
Step-by-step explanation:
First, let's factor that quadratic on the right:
[tex]x^2+6x+9[/tex] happens to factor nicely into [tex](x+3)^2[/tex], and putting that into our expression gets us
[tex](x+3)-x(x+3)^2[/tex]
Factoring out an (x + 3) from each term, we get
[tex](x+3)[1-x(x+3)][/tex]
Simplifying that expression on the right:
[tex](x+3)(1-x^2-3x)[/tex]
We can't factor that right-side expression any more, so we can just leave it like that!
