Answer:
44º
Step-by-step explanation:
We are given that a triangle QRS
QR=20 units
RS=24 units
QS=34 units
We have to find the measure of angle Q.
We know that cosine law
[tex]a^2=b^2+c^2-2bc cos A[/tex]
Using the formula
[tex](24)^2=(20)^2+(34)^2-2\times 20\times 34 cos Q[/tex]
[tex]576=1556-1360 cosQ[/tex]
[tex]1360osQ=1556-576[/tex]
[tex]1360 cos Q=980[/tex]
[tex]cos Q=\frac{980}{1360}[/tex]
[tex]cos Q=0.72[/tex]
[tex]Q=cos^{-1}(0.72)[/tex]
[tex]Q=44^{\circ}(approx)[/tex]
