Answer:
2 seconds
Step-by-step explanation:
Given that:
h = -16t² + 28t + 8
Using quadratic formula:
[tex]\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]
where;
a = -16
b = +28
c = +8
[tex]= \dfrac{-(28) \pm \sqrt{(28)^2 - 4(-16)(8)}}{2(-16)}[/tex]
[tex]= \dfrac{-(28) \pm \sqrt{784+512}} {-32}[/tex]
[tex]= \dfrac{-(28) + \sqrt{784+512}} {-32} \ \ OR \ \ = \dfrac{-(28) - \sqrt{784+512}} {-32}[/tex]
[tex]=- \dfrac{1}{4} \ \ OR \ \ 2[/tex]
Since we are considering the positive value; Then it will take the snowboarder 2 seconds before it hits the ground.
