Airline fares for a flight from Dallas to Austin are $30 for first class and $25 for tourist class. If a flight had 52 passengers who paid $1360, how many first class and tourist class passengers were there?​

Respuesta :

There were 40 tourist class passengers and 12 first class passengers. Β 

Explanation:

Let the number of passengers who booked for tourist class be

=

x

Then, number of passengers who booked for first class

=

52

βˆ’

x

According to question,

Total money paid = $25(tourist class)+$30(first class) Β 

$

1360

=

$

25

(

x

)

+

$

30

(

52

βˆ’

x

)

1360

=

25

x

+

1560

βˆ’

30

x

1360

βˆ’

1560

=

25

x

βˆ’

30

x

βˆ’

200

=

βˆ’

5

x

x

=

βˆ’

200

βˆ’

5

x

=

40

So, there were 40 tourist class passengers.

Now first class passengers

=

52

βˆ’

x

=

52

βˆ’

40

=

12

∴

There were 40 tourist class passengers and 12 first class passengers. Β 

As a check

Total money paid = $25(tourist class)+$30(first class) Β 

R

H

S

=

$

25

(

40

)

+

$

30

(

12

)

$

1000

+

$

360

=

$

1360

L

H

S

=

$

1360

Hence verified.