Answer:
a)60°
b)BD=10
c)AB=20
d)100√3
Step-by-step explanation:
B
let's BD be x
according to the question
[tex] \tan( {30}^{o} ) = \frac{x}{10 \sqrt{3} } [/tex]
[tex] \frac{ \sqrt{3} }{3} = \frac{x}{10 \sqrt{3} } [/tex]
[tex]3x = 10 \sqrt{3} \times \sqrt{3} [/tex]
[tex]3x = 30[/tex]
[tex]x = 10[/tex]
therefore
BD=10
c)
according to Pythagoras theorem
a²+b²=c²
c=√a²+b²
c=√10²+(10√3)²
c=√100+300
c=√400
c=20
D)
the two triangles are congruent
so AC=2(10√3)
=20√3
as we know
area of a triangle =
½bh
=½×20√3×10
=10√3×10
=100√3
this will guide you
