PLEASE HELP (100)

A block M, with mass of 4 kg, is released from rest and slides down a ramp that is angled at 28° above the horizontal (from the bottom of the ramp). The length of the ramp, d, is 3 meters. How much work is done by the gravitational force as the block slides down the ramp?

Respuesta :

Answer:

The work done will be [tex]W=55.27\: J[/tex]

Explanation:

The work equation is given by:

[tex]W=F\cdot x[/tex]

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

[tex]F_{x-direction}=mgsin(28)[/tex]

Therefore, the work done will be:

[tex]W=mgsin(28)*3[/tex]

[tex]W=4*9.81*sin(28)*3[/tex]

[tex]W=55.27\: J[/tex]

I hope it helps you!