Answer:
11860.22 rev/hour
Step-by-step explanation:
The diameter if a cylinder, d = 21.02 inches
Radius, r = 10.51 inches
or
r = 0.875 feet
The linear speed of a point on the cylinder's surface is 18.12 ft/sec.
We need to find the angular speed of the cylinder.
The relation between the linear speed and the angular speed is given by :
[tex]v=r\omega[/tex]
Where
[tex]\omega[/tex] is angular speed
[tex]\omega=\dfrac{v}{r}\\\\\omega=\dfrac{18.12}{0.875}\\\\\omega=20.7\ rad/s[/tex]
or
[tex]\omega=11860.22\ rev/hour[/tex]
So, the required angular speed of the cylinder is 11860.22 rev/hour.
