Answer:
[tex]\dfrac{x^3-2x^2+4x-3}{x-2}[/tex]
Step-by-step explanation:
The given equation is :
[tex]x^2+\dfrac{4x-3}{x-2}[/tex]
We need to decompose this equation.
We have,
[tex]x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}[/tex]
So, [tex]\dfrac{x^3-2x^2+4x-3}{x-2}[/tex] is the decomposed form of the given expression.
