Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use?

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25-01-2021
Mathematics

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Jeremy wants to determine the number of solutions for the equation below without actually solving the equation. Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3 Which method should Jeremy use?

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fichoh fichoh · Answer 1 · 2021-01-27T03:07:08+01:00

Options :

Determine whether the equation has the form a = a, and if it does, the equation has infinitely many solutions. Determine whether the equation has the form a = b, and if it does, the equation has no solution. Determine whether the equation has the form x = a, and if it does, the equation has one solution. Determine whether the equation has the form x = 0, and if it does, the equation has no solution.

Answer:

Determine whether the equation has the form x = a

Step-by-step explanation:

Negative 3 (x + 1) + 3 x = negative 3 (x minus 1) + 3

-3(x + 1) + 3x = - 3(x - 1) + 3

If the equation has the form x =a, where a is the unknown and a is the value of the unknown 'x'

Expanding :

-3x - 3 + 3x = - 3x + 3 + 3

-3x + 3x -3 = - 3x + 6

-3 = - 3x + 6

-3 - 6 = - 3x

-9 = - 3x

x = 9/3

x = 3