Answer:
The formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Explanation:
Iron (ii) ions, Fe²⁺ have a positive charge of +2. Chromate ions, CrO₄²⁻, on the other hand have a positive charge of -2. When iron (ii) ions and chromate ions combine two form a compound, each ion will contribute a mole of ion towards the formation of the compound. This is in line with the idea that a compound carries no charge. The positive charge (+2) of the iron (ii) ions are balanced by the negative charge of the chromate ions as shown mathematically as follows;
+2 + (-2) = 0; i.e. Fe²⁺ + CrO₄²⁻ = FeCrO₄
Therefore, the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
The formula formed by the compound by Iron ii ions and chromate ions will be FeCrO₄
Iron (ii) ions [tex]\rm Fe^{2+}[/tex] have a positive charge of +2. Chromate ions, [tex]\rm CrO_3^{2-}[/tex] on the other hand, have a positive charge of -2.
When iron (ii) ions and chromate ions combine to form a compound, each ion will contribute a mole of ion towards the formation of the compound.
This is in line with the idea that a compound carries no charge. The positive charge of the iron (ii) ions 2+ are balanced by the negative charge of the chromate ions -2 as shown mathematically as follows;
[tex]\rm +2+(-2)=0[/tex]
[tex]\rm Fe^{2+} +CcrO_4^{2-}=FeCrO_4[/tex]
Thus the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
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