Respuesta :
Answer:
i. Predicted chi-square value(x^2)?______ 22.35
ii. Â df_______ 6-1= 5
iii. Using the critical values table, determine the predicted P value
The P-Value is .050985 for 5 df and 0.05 significance level. The result is not significant at p < .01.
The P-Value is .010362 for 5 df and 0.01 significance level. The result is not significant at p < .01.
Step-by-step explanation:
Phenotype   Predicted ( o)    Expected (e)      (o-e)      (o-e)²/e
            (observed)
A- normal     19         3/4 * (1/4)= 3/16  25.5    -6.5      1.66
O  normal     5          1/4 * (1/4)= 1/16   8.5     -3.5       1.44
A trait        70         3/4 * (1/2)= 3/8   51      19        7.07
O  trait        25         1/4 * (1/2)= 1/8    17       8        3.67
A  Disease     13        3/4 * (1/4)= 3/16   25.5    -12.5      6.13
O  Disease    4         1/4 * (1/4)= 1/16     8.5   -4.5       2.38
            136                        136             22.35
i. What is your predicted chi-square value(x^2)?______ 22.35
ii. Calculate df_______ 6-1= 5
iii. Using the critical values table, determine the predicted P value
The critical region for alpha =0.05 is χ² ≥ χ² (0.05,5) = 11.02
The P-Value is .050985. The result is not significant at p < .01.
The critical region for alpha =0.01 is χ² ≥ χ² (0.01,5) = 15.00
The P-Value is .010362. The result is not significant at p < .01.
The calculated value of chi square is  22.35  which is greater than  15.00  and 11.02 , the critical regions at alpha 0.05 and 0.01
Therefore it falls in the critical region and the result is insignificant.