Have to find x,y and z

Answer:
x=2, y=5
Step-by-step explanation:
the triangle that x is in is a right triangle (don't remember the theorem sorry)
use pythagorean theorem (a^2 + b^2 = c^2)
x is the hypotenuse(c)
1 squared plus /3 squared =c squared
1+3= c squared
4= c squared
c=2
x=2
find y using pythagorean theorem as well
/12 squared plus 2 squared = y squared
y is the hypotenuse
12+4=y squared
16= y squared
4=y
add one to account for that extra little piece
y=5
... I don't see z
Answer:
y= if it is the hypoteneuse for the whole triangle it √16 or 4, if it is the side of the smaller triangle it is 3
x=√4 which is 2
z= I don't think ther's a z