Slvmptd
contestada

Write the equation of a line that is perpendicular to the given line and that passes through the
given point.
y-2= 7/3 (x + 5);(-4,9)
Oy-9=-3/7(x-4)
Oy-9= 3/7(x-4)
Oy- 9= -3/7(x+4)
Oy- 9= -3/7(x+4)

Respuesta :

imtiazkalwar

Answer:

[tex]y-9=-\frac{3}{7} (x+4)[/tex]

Step-by-step explanation:

Slopes are negative reciprocals when two lines are perpendicular

[tex]m= - \frac {3}{7}[/tex]

Equation of straight line in point-slope form is given as

[tex]y-y_1=m(x-x_2)[/tex]

Here [tex](x_1, y_1)= (-4, 9)[/tex]

[tex]y-9=-\frac{3}{7} (x+4)[/tex]

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