Answer:
[tex]K_1=4K_2[/tex]
Explanation:
Kinetic energy is given by
[tex]K=\dfrac{1}{2}mv^2[/tex]
m = Mass of object
v = Velocity of object
Here mass is constant so
[tex]K\propto v^2[/tex]
[tex]v_1[/tex] = Intial velocity of the car = 20 m/s
[tex]v_2[/tex] = Final velocity of the car = 10 m/s
[tex]\\dfrac{K_1}{K_2}=\dfrac{v_1^2}{v_2^2}\\\Rightarrow \dfrac{K_1}{K_2}=\dfrac{20^2}{10^2}\\\Rightarrow \dfrac{K_1}{K_2}=4\\\Rightarrow K_1=4K_2[/tex]
So, a car moving at 20 m/s has four times the translational kinetic energy of the same car moving at 10 m/s.
