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The half-life of the element radon (Rn86) is 3.8 days. In a sample originally containing 1 gram of radon, the amount of left over days is given by the model () = (0.5)t/3.8 a) How much radon will be present after 7.6 days? b) How much radon will be present after 10 days?

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Answer:

a.0.25 g

b.0.16 g

Step-by-step explanation:

We are given that

Half-life of the element radon=3.8 days

Mass of sample of radon=1 g

The amount of radon left after t days is given by

[tex]A(t)=(0.5)^{\frac{t}{3.8}}[/tex]

a.

We have to find the amount of radon left after 7.6 days.

Substitute t=7.6 in the equation

Then, we get

[tex]A(7.6)=(0.5)^{\frac{7.6}{3.8}}[/tex]

[tex]A(7.6)=0.25 g[/tex]

Hence, the amount of radon will be present after 7.6 days=0.25 g

b. We have to find the amount of radon left after 10 days.

Substitute t=10 in the equation

Then, we get

[tex]A(10)=(0.5)^{\frac{10}{3.8}}[/tex]

[tex]A(10)=0.16g[/tex]

Hence, the amount of radon will be present after 10 days=0.16 g

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