Answer:
Explanation:
If we consider the traits Q and R individually, then
P(Q) = 75% (Q is dominant, from hetero-zygous parents)
similarly
P(R) = 75% (Q is dominant, from hetero-zygous parents)
Assuming the two alleles P & Q are indepedent, then
P(Q and R) = 75% * 75% = 56.25%
Out of 64 offsprings, we expect 75*56.25% = 9/16*64 = 36 express both Q and R traits, on the average.
For the given experiment 36 offspring out of 64 will produce both Q and R traits.
Di-hybrid Cross:
It is cross of organisms in which scientist perform the experiment keeping two traits in mind.
One parent is pure and dominant while another is Heterozygous for traits.
The parental genotypes will be,
RRQQ x RrQq
The gametes will be,
RQ, Rq, rQ, and rq
The cross,
RQ Rq rQ rq
RQ RQRQ RQRq RQrQ RQrq
Probability, If the traits Q and R expressed
P(Q) = 75% (Q is dominant, from heterozygous parents)
P(R) = 75% (Q is dominant, from heterozygous parents)
Probability, if two alleles P & Q are independent, then
P(Q & R) = 75% x 75% = 56.25%
The offspring that express both alleles, out of 64 offspring,
[tex]\bold {75 \times 56.25\% = \dfrac {9}{16\times 64} = 36 }[/tex]
Therefore, for the given experiment 36 offspring out of 64 will produce both Q and R traits.
To know more about di-hybid cross,
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