Answer:
x+y=28
70x+140y=3360
8 cats, 20 dogs were sold
Step-by-step explanation:
Let x=cats y=dogs
We know that a total of 28 pets were sold which means that
x+y=28
We also know that they made 3360 which means that
70x+140y=3360
It doesn't really say if you need to solve this but I will anyways
We use the first equation (x+y=28) and subtract 28 and y from both sides to get
x-28= -y we can then divide both sides by -1 so y can be a positive
-x+28=y
This is what y equals in terms of x and so we can plug this in for y in the second equation
70x+140(-x+28)=3360
Distribute the 140 and get
70x-140x+3920=3360
Add like terms and subtract 3920 to get
-70x=-560
divide both sides by -70 and get
x=8
We now know that 8 cats were sold and can plug this value into any equation to solve for y ( I will be using the first one because that's easiest)
8+y=28
subtract 8 and get
y=20
A system of equations that matches the situation is:
1) d + c = 28.................Equation 1
2)140d + 70c = 3360............Equation 2
This question has to do with Algebraic equations.
Let's represent
Number of dogs = d
Number of cats = c
A pet store is selling dogs for $140 and cats for $70. If 28 pets were sold and they made $3,360.
We have two algebraic systems of equations for the above statements
1) d + c = 28.................Equation 1
2) $140 x d + $70 x c = $3,360
140d + 70c = 3360............Equation 2
To learn more, visit the link below:
brainly.com/question/20041220
