HaileyTheGoth
contestada

Given Set \(M:\ 0,\ 1,\ 3,\ 4,\ 7\) and Set \(N:\ 1,\ 2,\ 3,\ 4,\ 5,\ 9\).

Calculate the mean and mean absolute deviation for both sets. Then, answer the following questions.

1. How many data points in Set M are closer than one mean absolute deviation from the mean of Set M?
2. How many data points in Set N are further than two mean absolute deviations from the mean of Set N?
3. Find the difference between the two means. How does this difference relate to the mean absolute deviation of each set? For example, is it the same as the mean absolute deviation, twice as much, half as much, etc?

Respuesta :

francenemae2007

Answer:

1. 5

2. 6

3 . difference between the two means is 2,5,9

The number of data points in Set M are closer than one mean absolute deviation from the mean of Set M is; 5

What is the mean absolute deviation?

We are given;

Set M: 0, 1, 3, 4, 7

Set N: 1, 2, 3, 4, 5, 9

Mean of set M = (0 + 1 + 3 + 4 + 7)/5 = 3

Mean of set N = (1 + 2 + 3 + 4 + 5 + 9)/6 = 4

1) From the mean of set M, we using online calculator, the mean absolute deviation of set M is 2. Thus, the number of data points closer than one mean absolute deviation from the mean of Set M is 5.

2) From the mean of set N, we using online calculator, the mean absolute deviation of set N is 2. Thus, the number of data points closer than one mean absolute deviation from the mean of Set N is 6.

3) The difference between the two means is;

4 - 3 = 1

Read more about mean absolute deviation at; https://brainly.com/question/16586775

Otras preguntas