A tourist ignores the warning signs and leaves food in his car while he goes for a hike. A mama bear and her cub open the car door in six seconds. How long would it take each bear to open the car door alone if the cub needs 9 more seconds than the mama bear?

Respuesta :

Answer:

The mama bear can do it in 9

seconds. The cub can do it in 18

seconds.

Step-by-step explanation:

1/x+9+1/x=1/6

Using the together rate, it is found that it would take each bear 9 hours to open the car door alone.

What is the together rate?

The together rate is the sum of each separate rate.

In this problem, the rates are as follows:

Given

A tourist ignores the warning signs and leaves food in his car while he goes for a hike.

A mama bear and her cub open the car door in six seconds.

Together with rate: 1/6.

Mama's rate: 1/x.

Cub's rate: 1/(x + 9).

Therefore,

[tex]\rm \dfrac{1}{x}+\dfrac{1}{x+9}=\dfrac{1}{6}\\\\\dfrac{x+9+x}{x(x+9)}=\dfrac{1}{6}\\\\\dfrac{2x+9}{x(x+9)}=\dfrac{1}{6}\\\\ 6(2x+9)=x(x+9)\\\\12x+54=x^2+9x\\\\x^2+9x-12x-54=0\\\\x^2-3x-54=0\\\\ x^2+6x-9x-54=0\\\\ x(x+6)-9(x+6)\\\\(x-9)(x+6)=0\\\\x-9=0 \ x=9\\\\x+6=0 \ x=-6[/tex]

The value of time can not be negative.

Hence, It would take each bear 9 hours to open the car door alone.

To learn more about the together rate, you can take a look at brainly.com/question/25159431