Answer:
hello your question is incomplete attached below is the complete question
answer :
for  I1 =   [tex]\frac{1}{x^2} + \frac{4}{x^3}[/tex]   The integral converges
for  I2 =   [tex]\frac{2x + 6}{2(x^2 + 6x + 4 )}[/tex]  The integral diverges
for  I3 =  [tex]\frac{1}{x^2}[/tex]  The integral converges
for  I4 = 1  The integral diverges
Step-by-step explanation:
The similar integrands and the prediction ( conclusion )
for  I1 =   [tex]\frac{1}{x^2} + \frac{4}{x^3}[/tex]   The integral converges
for  I2 =   [tex]\frac{2x + 6}{2(x^2 + 6x + 4 )}[/tex]  The integral diverges
for  I3 =  [tex]\frac{1}{x^2}[/tex]  The integral converges
for  I4 = 1  The integral diverges
attached below is a detailed solution