Declare and implement a function called gameOver.gameOver receives a single 3x3 char[] [] array as a parameter, representing a tic-tac-toe board, with each cell containing either a X, a 0, or a (blank space). gameOver should return x if x has won the game, o ifo has won the game, and a blank space (' ') otherwise. Do not check the diagonals!

if((arr[0][0] == 'X' && arr[0][1] == 'X' && arr[0][2] == 'X') ||(arr[1][0] == 'X' && arr[1][1] == 'X' && arr[1][2] == 'X') || (arr[2][0] == 'X' && arr[2][1] == 'X' && arr[2][2] == 'X')||(arr[0][0] == 'X' && arr[1][0] == 'X' && arr[2][0] == 'X') ||(arr[0][1] == 'X' && arr[1][1] == 'X' && arr[2][1] == 'X') || (arr[0][2] == 'X' && arr[1][2] == 'X' && arr[2][2] == 'X')){

winner = 'X';

}

else if((arr[0][0] == 'O' && arr[0][1] == 'O' && arr[0][2] == 'O') ||(arr[1][0] == 'O' && arr[1][1] == 'O' && arr[1][2] == 'O') || (arr[2][0] == 'O' && arr[2][1] == 'O' && arr[2][2] == 'O')||(arr[0][0] == 'O' && arr[1][0] == 'O' && arr[2][0] == 'O') ||(arr[0][1] == 'O' && arr[1][1] == 'O' && arr[2][1] == 'O') || (arr[0][2] == 'O' && arr[1][2] == 'O' && arr[2][2] == 'O')){

winner = 'O';

}

return winner;

}

Explanation:

The function checks for the winning character by checking for matching rows and matching columns.

When either X or O fall in the any of the following 6 conditions , then that character (X or O) wins.

The position are:

Rows: (1) 00, 01 and 02 (2) 10, 11 and 12 (3) 20, 21 and 22

Columns: (4) 00, 10 and 20 (5) 01, 11 and 21 (6) 02, 12 and 22

So, the explanation is:

This defines the function gameOver

char gameOver(char arr[][3]){

This initializes winner to blank space

char winner = ' ';

If any of the condition stated above matches X, then X wins

if((arr[0][0] == 'X' && arr[0][1] == 'X' && arr[0][2] == 'X') ||(arr[1][0] == 'X' && arr[1][1] == 'X' && arr[1][2] == 'X') || (arr[2][0] == 'X' && arr[2][1] == 'X' && arr[2][2] == 'X')||(arr[0][0] == 'X' && arr[1][0] == 'X' && arr[2][0] == 'X') ||(arr[0][1] == 'X' && arr[1][1] == 'X' && arr[2][1] == 'X') || (arr[0][2] == 'X' && arr[1][2] == 'X' && arr[2][2] == 'X')){

winner = 'X';

}

If otherwise that it matches O, then O wins

else if((arr[0][0] == 'O' && arr[0][1] == 'O' && arr[0][2] == 'O') ||(arr[1][0] == 'O' && arr[1][1] == 'O' && arr[1][2] == 'O') || (arr[2][0] == 'O' && arr[2][1] == 'O' && arr[2][2] == 'O')||(arr[0][0] == 'O' && arr[1][0] == 'O' && arr[2][0] == 'O') ||(arr[0][1] == 'O' && arr[1][1] == 'O' && arr[2][1] == 'O') || (arr[0][2] == 'O' && arr[1][2] == 'O' && arr[2][2] == 'O')){

winner = 'O';

}

This returns the winner (either O, X or blank)

return winner;

See attachment for complete program which includes the main