Respuesta :
Answer:
The probability that the child will have type blood B equals 3/16.
Explanation:
Available data:
- Individuals with the rare Bombay blood phenotype lack both the A and B antigens in individuals and/or are of hh genotype.
- Cross between two parents that are both of I A I B Hh genotype
Cross: IAIB Hh   x   IAIB Hh
Gametes) IAH, IAh, IBH, IBh Â
        IAH, IAh, IBH, IBh
Punnett square)     IAH       IAh     IBH     IBh
          IAH    IAIAHH   IAIAHh   IAIBHH  IAIBHh
          IAh    IAIAHh   IAIAhh   IAIBHh   IAIBhh
          IBH    IAIBHH   IAIBHh   IBIBHH  IBIBHh
          IBh    IAIBHh   IAIBhh    IBIBHh  IBIBhh
F1) Genotype
- Â Â 1/16 IAIA HH
- Â Â 2/16 IAIAHh
- Â Â 1/16 IAIAhh
- Â Â 2/16 IAIBHH
- Â Â 4/16 IAIBHh
- Â Â 2/16 IAIBhh
- Â Â 1/16 IBIBHH
- Â Â 2/16 IBIBHh
- Â Â 1/16 IBIBhh
  Phenotype
- Â Â 3/16 Blood type A
- Â Â 6/16 Blood type AB
- Â Â 3/16 Blood type B
- Â Â 3/16 Blood type 0 Â