Answer:
The answer is
[tex] \frac{1}{2} \: and \: \frac{ \sqrt{2} }{2} [/tex]
Step-by-step explanation:
Let The point (X, Y)
Since half of the diameter is equal to 1
Then
[tex] {x}^{2} + {y}^{2} = 1[/tex]
Why is the measurement of angle is equal to 60, this triangle was equal
Then
[tex] {(x - 1)}^{2} + {y}^{2} = 1[/tex]
By comparing the equals together
[tex] {x}^{2} = {(x - 1)}^{2} \\ {x}^{2} = {x}^{2} - 2x + 1 \\ 2x = 1 \\ x = \frac{1}{2} \\ Compensation \: in \: any \: equation \\ then \: y = \frac{ \sqrt{2} }{2} [/tex]
