What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds

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Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

[tex]F = \frac{m(v-u)}{t} \\\\F = \frac{1600(40-15)}{4} \\\\F = 10,000 \ N[/tex]

The net power needed to change the speed of the vehicle is calculated as;

[tex]P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W[/tex]

The net power needed to change the speed of the vehicle is 275.000Watts

Power is the ratio of workdone with respect to the time taken.

  • Power = workdone/time
  • Workdone = force * distance/time
  • Workdone = Force * speed

Get the required force:

F = m(v-u)/t

F = 1600(40-15)/4

F = 1600(25)/4

F = 400 * 25

F = 10,000N

The required net power will be calculated as shown:

P = 1/2*F(u+v)

P = 1/2(10000)*(15+40)

P = 5000(55)

P = 275,000Watts

Hence the net power needed to change the speed of the vehicle is 275.000Watts

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