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Two stoves were turned off at the same time, and they both started to cool down. The following equation gives the temperature of the first stove (in degrees Celsius) as a function of time (in minutes). T = 180-1.55mT=180−1.55mT, equals, 180, minus, 1, point, 55, m The graph of the temperature of the second stove (in degrees Celsius) as a function of time (in minutes) is shown below. Which stove started at a higher temperature?

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AzeriaQt

Answer:

b & b

Explanation:

Two stoves were turned off at the same time, and they both started to cool down.

The following equation gives the temperature of the first stove (in degrees Celsius) as a function of time (in minutes).

T = 180-1.55mT=180−1.55mT, equals, 180, minus, 1, point, 55, m

The graph of the temperature of the second stove (in degrees Celsius) as a function of time (in minutes) is shown below.

Which stove started at a higher temperature?

Choose 1 answer:

Choose 1 answer:

(Choice A, Incorrect)

INCORRECT

The first stove

(Choice B, Checked, Correct)

CORRECT (SELECTED)

The second stove

(Choice C, Incorrect)

INCORRECT

The stoves started at the same temperature

Which stove cooled down at a greater rate?

Choose 1 answer:

Choose 1 answer:

(Choice A, Incorrect)

INCORRECT

The first stove

(Choice B, Checked, Correct)

CORRECT (SELECTED)

The second stove

(Choice C, Incorrect)

INCORRECT

The stoves cooled down at the same rate

B would be correct and so would be on the 2nd part