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Logan measured a line to be 7.4 inches long. If the actual length of the line is 7.7 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?
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tisonm23

Answer:

4.0541

Step-by-step explanation:

I don't know if this is correct but this is what I got.

You would take the error and divide it by the theoretical value and then multiply that by 100.

7.7 - 7.4 = 0.3

0.3 ÷ 7.4 = 0.04054054

0.04054054 x 100 = 4.05405405 (simplify) = 4.0541%

Hope I helped in any way

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