Answer:
0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability of independent events:
Suppose we have two events, A and B, that are independent. The probability of both happening is given by:
[tex]P(A \cap B) = P(A) \times P(B)[/tex]
In this question:
Event A: Selecting a prime number.
Event B: Selecting a number less than or equal to 3
Probability of selecting a prime number:
Between 1 and 10, we have 4 prime numbers(2,3, 5 and 7), out of 10. So
[tex]P(A) = \frac{4}{10}[/tex]
Probability of selecting a number less than or equal to 3:
Three numbers(1,2,3) out of 10. So
[tex]P(B) = \frac{3}{10}[/tex]
Probability of both:
[tex]P(A \cap B) = P(A) \times P(B) = \frac{4}{10} \times \frac{3}{10} = \frac{12}{100} = 0.12[/tex]
0.12 = 12% probability of first selecting a PRIME number, replacing it, then selecting a number less than or equal to 3
