YoonBloom1646 YoonBloom1646
  • 23-02-2021
  • Physics
contestada

A 75 kg baseball player runs at a velocity of 6 m/s and sliding 2 m what is the force of friction that acts upon him?

Respuesta :

samuelonum1
samuelonum1 samuelonum1
  • 26-02-2021

Answer:

1350N

Explanation:

Given data

mass= 75kg

velocity= 6m/s

distance= 2m

The expression for the applied force is given as

F= mv^2/d

Substitute

F= 75*(6)^2/ 2

F= 75*36/2

F= 2700/2

F= 1350N

Hence the force is 1350N

Answer Link

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