Answer:
Abelito had the greater average speed
Step-by-step explanation:
Given
Bobby:
[tex]Distance =4\ miles[/tex]
[tex]Time = 30\ minutes[/tex]
Abelito
[tex]Distance = 10\ miles[/tex]
[tex]Time = 48\ minutes[/tex]
Required:
Who had a greater average speed
Average speed (S) is calculated as:
[tex]S = \frac{Distance}{Time}[/tex]
We will make use of mph (miles per hour) as the unit of speed.
For Bobby:
[tex]S_B = \frac{4\ miles}{30\ minutes}[/tex]
Convert minute to hour
[tex]S_B = \frac{4\ miles}{0.5\ hr}[/tex]
[tex]S_B = 8mph[/tex]
For Abelito
[tex]S_A = \frac{10\ miles}{48\ minutes}[/tex]
Convert minute to hour
[tex]S_A = \frac{10\ miles}{0.8\ hr}[/tex]
[tex]S_A = 12.5mph[/tex]
By comparison: 12.5mph > 8mph
Hence: Abelito had the greater average speed
