Respuesta :
Work done = force*distance = mass*acceleration*distance
acceleration = 10/3 = 3.33 m/s^2
distance = ((0+10)/2)*3 = 15m
work done = 1500*3.33*15 = 74900 J
Power = workdone/time = 74900/3 = 25000 W
a. The work done on the car in this time interval is 75000 J.
b. And, the power delivered by the engine in this time interval is 25,000 watt.
Given that,
- A 1.50 x 103 kg car accelerates uniformly from rest to 10.0 m/s in 3.00 s.
Based on the above information, the calculation is as follows:
(a)
We know that
[tex]w = \frac{1}{2} \times m (v^2 - u^2)[/tex]
Here
Mass = [tex]1.50 \times 103 kg[/tex]
v= 10 m / s
u= 0 m / s
Now place it to the above formula
So, Work done is = 75000 J
(b)
[tex]Power P = W \div t\\\\= 75000 \div 3[/tex]
= 25000 Watt
Therefore the above are the answers.
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