yall pls help meeeee (brainliest btw)!!!!!

Colossal Elementary School had a mother/daughter painting weekend. On Saturday, eight mothers worked with 12 daughters to paint 220square feet of a large mural on a wall in the gymnasium. The next day, six moms worked with eight daughters to paint another 152square feet of the mural in the gym. Write and solve a system of equations to find how many square feet each mom painted and how many square feet each daughter painted. Assume all moms painted at the same rate and all daughters painted at the same rate.

Respuesta :

Answer:

Let m be the amount each mom can paint and d be the amount each daughter can paint.

On the first day, 8 mothers were painting so the mothers painted 8m square feet. 12 daughters also painted so the daughters painted 12d square feet. The total amount painted on the first day is then 8m+12d square feet. Since 220 square feet was painted on the first day, then 8m+12d=220.  Dividing both sides by 4 gives a simplified equation of 2m+3d=55.

On the second day, 6 mothers were painting so the mothers painted 6m square feet. 8 daughters also painted so the daughters painted 8d square feet. The total amount painted on the second day is then 6m+8d square feet. Since 152 square feet was painted on the second day, then 6m+8d=152

Multiply the first equation by -3 and then add it to the second equation to eliminate m and solve for d:

d=13

2m+3d=55

2m+3(13)=55

2m+39=55

2m=16

m=8

Therefore each mom painted 8 square feet and each daughter painted 13 square feet.