Answer: 0.45 moles of [tex]H_2O[/tex] will be produced from 0.15 moles of propanol.
Explanation:
The balanced chemical reaction is:
[tex]2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O[/tex]
[tex]C_3H_6O[/tex] is the limiting reagent as it limits the formation of product and [tex]O_2[/tex] is the excess reagent.
According to stoichiometry :
2 moles of [tex]C_3H_6O[/tex]produces = 6 moles of [tex]H_2O[/tex]
Thus 0.15 moles of [tex]V[/tex] will produce=[tex]\frac{6}{2}\times 0.15=0.45moles[/tex] Â of [tex]H_2O[/tex]
Thus 0.45 moles of [tex]H_2O[/tex] will be produced from 0.15 moles of propanol.
