A carpenter designs a tabletop in the shape of an ellipse 7 feet long and 4 feet wide then, the equation of that ellipse would be [tex]\dfrac{ x^2}{12.25} + \dfrac{ y^2}{4} = 1[/tex]
Suppose that the major axis is of the length 2a units, and that minor axis is of 2b units, and let the ellipse is centered on (h,k) with a major ellipse parallel to x-axis, then the equation of that ellipse would be:
[tex]\dfrac{(x-h)^2}{a^2} + \dfrac{(y-k)^2}{b^2} =1[/tex]
Coordinates of its foci would be: [tex](h \pm c, k)[/tex] where [tex]c^2 = a^2 - b^2[/tex]
If its major axis is parallel to y-axis, then,
Coordinates of its foci would be: [tex](h , k\pm c)[/tex] where [tex]c^2 = a^2 - b^2[/tex]and its equation would be:
[tex]\dfrac{(x-h)^2}{b^2} + \dfrac{(y-k)^2}{a^2} =1[/tex]
A carpenter designs a tabletop in the shape of an ellipse 7 feet long and 4 feet wide.
The carpenter sketches a drawing of the tabletop on a coordinate plane.
The center of the tabletop is at the origin, the length falls along the x-axis, and the width falls along the y-axis.
then, the equation of that ellipse would be:
[tex]\dfrac{ x^2}{12.25} + \dfrac{ y^2}{4} = 1[/tex]
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