Answer:
[tex]x = 6[/tex]
Carl is correct
Step-by-step explanation:
Given
[tex]\frac{6}{3} = \frac{12}{x}[/tex]
See attachment
Required
Is Carl correct?
Using the side spotter theorem, the proportion is:
[tex]\frac{AB}{BC} = \frac{AE}{ED}[/tex]
This gives:
[tex]\frac{6}{3} = \frac{12}{x}[/tex]
This proportion is equivalent to Carl's.
Hence, Carl is correct.
Solving further: Cross Multiply
[tex]6 * x = 12 * 3[/tex]
[tex]6 * x = 36[/tex]
Make x the subject
[tex]x = \frac{36}{6}[/tex]
[tex]x = 6[/tex]
