Answer:
52.38 inch² & 261.90 inch²
Step-by-step explanation:
Here we need to find the area of the sector . So according to formula we know the area of sector as ,
[tex]\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }[/tex]
Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,
=> Area = ∅/ 360° × π r²
=> Area = 60°/360° × 22/7 × (10in.)²
=> Area = 1/6 * 22/7 * 100 in²
=> Area = 52 .380 in²
★ Hence the area of the red sector is 52.38 inch².
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Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .
=> Area = 300/360 × 22/7 × 100 in²
=> Area = 261. 90 in²
★ Hence the area of blue sector is 261.90 inch².
[tex]\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}[/tex]
[tex]\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}[/tex]
