A biologist wants to compare the proportions of rainbow trout infected with whirling disease (an illness of
trout and salmon caused by a microscopic parasite) coming from two separate watersheds. For each
watershed, the biologist will collect a random sample of trout and record the proportion infected in the
sample. The biologist intends to estimate the difference for all trout in the two watersheds. Assuming all
conditions for inference are met, which of the following is the most appropriate method for the biologist to
use to analyze the results?
A
A one-sample z-interval for a population proportion
B
A one-sample z-interval for a sample proportion
с
A one-sample z-interval for a difference in sample proportions
D
A two-sample z-interval for a difference in population proportions
E
A two-sample z-interval for a difference in sample proportions

Respuesta :

Answer:

D

Step-by-step explanation:

Because, the biologist wants to find the difference between the population of trouts from two watershed,

A biologist wants to compare the proportions of rainbow trout infected with whirling disease (an illness of trout and salmon caused by a microscopic parasite) coming from two separate watersheds.

The biologist will collect a random sample of trout and record the proportion infected in the sample The biologist intends to estimate the difference for all trout in the two watersheds

According to the given question, the most appropriate method for the biologist will be -A two-sample z-interval for a difference in population proportions

Because,Biologist wants to compare the proportions of rainbow trout infected with whirling disease and find the difference between the population of the trouts from two watershed .

Therefore , Statement D is the Correct

Learn more about Similar questions here : https://brainly.com/question/1904003