In the given figure, ABCD is a rectangle in which ∠APB = 100°. The value of x is:

Answer:
Given that angle APB = 100°
Angle CPB = 180°- 100°. (Angle APB and CPB form a linear pair)
We know all triangles formed here are isosceles
Therefore,
We can take angle PBC= angle PCB = x
Now,
Angle CPB+ x + x = 180°. ( Triangle sum property)
100° + 2x = 180°
2x = 180°- 100°
2x= 80°
x= 80°/2
x= 40°
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