contestada

A 60-kg passenger is in an elevator which is initially at rest. The elevator starts to travel downward. It reaches a downward speed of 7m/sec in a time of 4 seconds

Respuesta :

Lanuel

Answer:

a. Acceleration = 1.75 m/s²

b. Force = 105 Newton.

Explanation:

Given the following data:

Mass = 60kg

Final velocity = 7m/s

Time = 4 seconds

Required to find the acceleration and force of the body;

a. To find the acceleration;

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Where;

  • a is acceleration measured in [tex]ms^{-2}[/tex]
  • v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]
  • t is time measured in seconds.

Since the elevator is starting from rest, its initial velocity is equal to 0m/s.

Substituting into the equation, we have;

[tex]Acceleration = \frac{7 - 0}{4}[/tex]

[tex]Acceleration = \frac{7}{4}[/tex]

Acceleration = 1.75 m/s²

b. To find the force;

[tex] Force = mass * acceleration [/tex]

Substituting into the equation, we have;

[tex] Force = 60 * 1.75[/tex]

Force = 105 Newton.

Otras preguntas