Answer:
[tex] \purple {\bold {m\angle A =70\degree}} [/tex]
Step-by-step explanation:
ABCD is a trapezoid. AB || DC and AD is transversal...(given)
[tex] AD \cong BC.. (given) [/tex]
Therefore, ABCD is an isosceles trapezoid.
Measures of base angles of isosceles trapezoid are equal.
[tex] \therefore m\angle D =m\angle C[/tex]
[tex] \because m\angle C =110\degree... (given) [/tex]
[tex] \therefore m\angle D =110\degree [/tex]
[tex] m\angle A+ m\angle D =180\degree [/tex]
(interior angles on the same side of transversal)
[tex] m\angle A+ 110\degree =180\degree [/tex]
[tex] m\angle A =180\degree -110\degree [/tex]
[tex] \purple {\bold {m\angle A =70\degree}} [/tex]
