. A solid metal cylinder of radius 5 cm and height 12 cm is melted down and recast into a
cone of base radius 10 cm.
Calculate the height of the cone.

Respuesta :

Answer:

H = 9 cm

Step-by-step explanation:

The volume of the cylinder equal the volume

[tex]\pi\: \: {r}^{2} \times hcy = \frac{1}{3} \pi {r}^{2} \times hco \\ hco = 9 \: cm[/tex]

The height of the cone is 9 cm.

The volume of the cylinder = The volume of the Cone

This is because the exact metal cylinder was recast into a cone.

Volume of a cylinder:

volume = πr²h

r = 5 cm

h = 12 cm

volume = π × 5² × 12

volume = π × 25 × 12

volume  = 300π

Volume of a cone:

volume = 1 / 3 πr²h

r = 10 cm

h = ?

300π = 1 / 3 × π × 10² × h

300π = 100πh / 3

900π = 100πh

h = 900π / 100π

h = 9 cm

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