[tex]\displaystyle\bf\\\frac{x^3+y^3}{x+y}=?\\\\ ~~~~~~~~~~~We~use~the~formula:~~~~x^3+y^3=(x+y)(x^2-xy+y^2)\\\\\frac{x^3+y^3}{x+y}=\frac{(x+y)(x^2-xy+y^2)}{x+y}=\boxed{\bf x^2-xy+y^2}\\\\We~simplified~the~fraction~with~(x + y)[/tex]