Answer:
[tex] \huge \boxed{ \boxed{ \sf \: x = 5.2 \atop\sf y = 6}}[/tex]
Step-by-step explanation:
to understand this
you need to know about:
given:
- [tex] \theta = {30}^{o} [/tex]
- opp:3
to find:
- adjacent (x)
- hypotenuse (y)
tips and formulas:
- [tex] \tan( {30}^{o} ) = \frac{ \sqrt{3} }{3} [/tex]
- tan(a)=opp/adj
- sin(a)=opp/hypo
- [tex] \sin( {30}^{o} ) = \frac{1}{2} [/tex]
let's solve:
according to the question
[tex] \tan( {30}^{o} ) = \frac{3}{x} [/tex]
[tex] \frac{ \sqrt{3} }{3} = \frac{3}{x} \\ x\sqrt{3} = 9 \\ x = \frac{9}{ \sqrt{3} } \\ x = 3\sqrt{3} \\ x = 5.2[/tex]
according to the question
[tex] \sin( {30}^{o} ) = \frac{3}{y} [/tex]
[tex] \frac{1}{2} = \frac{3}{y} [/tex]
[tex]y = 6[/tex]
