Slove the following:

Answer:
let required no be x
[tex] \frac{1}{7} = \frac{x}{42} [/tex]
by doing crisscrossed multiplication
[tex]42 \times 1 = 7 \times x[/tex]
42=7x
dividing both side by 7
[tex] \frac{42}{7} = 7x \div 7[/tex]
6=x
therefore x=6
therefore value of remaining no.is 6
Step-by-step explanation:
solution
here,
let, the required number be x
1/7=x/42
or, 42= 7x
or, x= 42/ 7
therefore, x= 6
hope this helps u...